如何在DOS批处理脚本中将sring转换为十六进制？
例如,将“abcd”转换为“61626364”.
因为’a’是0x61 ……
例如,将“abcd”转换为“61626364”.
因为’a’是0x61 ……
我试图从网上找到一个解决方案,但是找不到我的答案.
@echo off
setlocal EnableDelayedExpansion
rem Store the string in chr.tmp file
set /P "=%~1" < NUL > chr.tmp
rem Create zero.tmp file with the same number of Ascii zero characters
for %%a in (chr.tmp) do fsutil file createnew zero.tmp %%~Za > NUL
rem Compare both files with FC /B and get the differences
set "hex="
for /F "skip=1 tokens=2" %%a in ('fc /B chr.tmp zero.tmp') do set "hex=!hex!%%a"
del chr.tmp zero.tmp
echo %hex%
输出示例：
C:\> test.bat abcd 61626364