我想用正则表达式替换出现在带空格的字母之间的短划线.例如,用ab cd替换ab-cd
以下匹配字符 – 字符序列,但也替换字符[即ab-cd导致d,而不是ab cd,因为我希望]
new_term = re.sub(r"[A-z]\-[A-z]"," ",original_term)
我如何适应以上只能取代 – 部分？
您需要捕获 – 组之前和之后的字符并将其用于替换,即：
import re subject = "ab-cd" subject = re.sub(r"([a-z])\-([a-z])",r"\1 \2",subject,re.IGnorECASE) print subject #ab cd
DEMO
http://ideone.com/LAYQWT
REGEX EXPLANATION
([A-z])\-([A-z]) Match the regex below and capture its match into backreference number 1 «([A-z])» Match a single character in the range between “A” and “z” «[A-z]» Match the character “-” literally «\-» Match the regex below and capture its match into backreference number 2 «([A-z])» Match a single character in the range between “A” and “z” «[A-z]» \1 \2 Insert the text that was last matched by capturing group number 1 «\1» Insert the character “ ” literally « » Insert the text that was last matched by capturing group number 2 «\2»