我正在尝试启动服务,然后打开套接字与服务器连接.
在按钮上单击我创建新线程然后启动服务.
Thread t = new Thread(){
public void run(){
mIntent= new Intent(MainActivity.this,ConnectonService.class);
mIntent.putExtra("KEY1","Value used by the service");
context.startService(mIntent);
}
};
t.start();
然后在服务上,我尝试打开套接字并与服务器连接
@Override
public int onStartCommand(Intent intent,int flags,int startId) {
//Todo do something useful
try {
InetAddress serverAddr = InetAddress.getByName(SERVER_IP);
socket = new Socket(serverAddr,SERVERPORT);
Scanner scanner = new Scanner(socket.getInputStream());
message = scanner.nextLine();
} catch (IOException e) {
e.printstacktrace();
}
return Service.START_NOT_STICKY;
}
但是当我打电话给我时,我有错误
08-30 08:56:49.268: E/AndroidRuntime(3751): java.lang.RuntimeException: Unable to start service com.example.testofconnection.ConnectonService@40ef02a8 with Intent { cmp=com.example.testofconnection/.ConnectonService (has extras) }: android.os.networkonmainthreadException*
我认为问题是服务在主线程上,但是我找不到如何在新的(独立)线程上启动服务以保持连接活动？
解决方法
您可以使用IntentService.只需使用主线程中的Intent正常启动它. onHandleIntent()方法在后台线程中执行.把你的套接字代码放在那里.这是一个示例代码.
public class MyIntentService extends IntentService {
public MyIntentService() {
super("MyIntentService");
}
@Override
protected void onHandleIntent(Intent intent) {
// this method is called in background thread
}
@Override
public IBinder onBind(Intent intent) {
return null;
}
}
在您的活动中,您将按以下方式启动服务.
startService(new Intent(this,MyIntentService.class));
如果您需要持久的服务,您可以创建一个正常的服务并在那里启动一个线程.这是一个例子.确保将其作为“前台”服务启动.这将使服务运行更长时间而不会被Android杀死.
public class MyAsyncService extends Service {
private Runnable runnable = new Runnable() {
@Override
public void run() {
while(true) {
// put your socket-code here
...
}
}
}
@Override
public void onCreate() {
// start new thread and you your work there
new Thread(runnable).start();
// prepare a notification for user and start service foreground
Notification notification = ...
// this will ensure your service won't be killed by Android
startForeground(R.id.notification,notification);
}
}