我已经设置了一个window.onerror处理程序来捕获错误.它的目的？要在每次发生错误时连接一个字符串,然后另一个处理程序window.onunload将其发送到服务器. (据推测有所有错误).
问题是,它只能发送第一个错误,因为在第一次触发onerror处理程序事件后,错误没有被捕获,因此脚本终止…
有没有解决的办法？
ErrorManager: (function () {
function Init(message) {
InitErrorHandler();
InitAjaxHandler();
setTimeout("Interface.ErrorManager.SendErrorsToAjax()",8000);
}
function InitErrorHandler() {
Data.ErrorHandlerText = "";
Data.ErrorHandlerCount = 0;
window.onerror = function(errorMessage,url,line) {
if(IsInIgnoreList(errorMessage)) { return; }
Data.ErrorHandlerText += ("Error: "+(Data.ErrorHandlerCount+1)+" <br /><br />");
//Get error specific info
Data.ErrorHandlerText += escape(errorMessage) + "<br />";
Data.ErrorHandlerText += escape(url) + "<br />";
Data.ErrorHandlerText += escape(line) + "<br />";
Data.ErrorHandlerCount++;
console.log("BOOM"+errorMessage);
}
}
function InitAjaxHandler() {
window.onbeforeunload = function() { //when browser closed
Data.ErrorHandlerCount > 0 && SendErrorsToAjax();
}
}
function SendErrorsToAjax() {
PrepareErrorsForAjax();
$.getJSON(Interface.Utility.PrefixURL('/ajax/sendFeedback/handlejserrors/'+Data.ErrorHandlerText));
}
function IsInIgnoreList(str) {
return str.indexOf('nsIDOMSVGLocatable') != -1 ? true : false;
}
function PrepareErrorsForAjax() {
var preText = "<br /><br />A user has encountered a few errors: <br /><br />";
//Get session info
var userAgent,activePageID,accountNO,consumerNO;
userAgent = escape(navigator.userAgent);
preText += "User agent: "+userAgent+" <br />";
if($.mobile.activePage) {
activePageID = $.mobile.activePage.attr('id');
preText += "Page ID: "+activePageID+" <br />";
}
//Get info that may or may not be set
console.log("AUTH JSON "+Data.authJSON);
console.log("CONSUMER JSON "+Data.authJSON.consumers);
if(Data.authJSON && localStorage.lastConsumerNo) {
preText += "Account Number: " +Data.authJSON.accountId+" <br />";
preText += "Consumer Number: "+ localStorage.lastConsumerNo+" <br />";
}
preText += "<br /> The following errors were encountered:<br /><br />";
Data.ErrorHandlerText = preText + Data.ErrorHandlerText;
}
return {
Init: Init,SendErrorsToAjax: SendErrorsToAjax
}
})(),
解决方法
将其添加到单独的< script>标记,以便window.onerror不会被其他脚本标记中的脚本错误所困扰.
DEMO
<script>
var trackerrorMsg = '';
window.onerror = function(msg,lineNo) {
trackerrorMsg += msg;
}
</script>
请注意,以上内容并不会阻止在浏览器控制台中记录错误.上面的代码只是为了跟踪错误..您应该使用try…catch来处理任何特定部分中的错误.
DEMO – 显示在同一执行上下文中它不起作用时.