为什么我得到这个错误：
Catchable Fatal error: Object of class Card Could not be converted to
string in /f5/debate/public/Card.PHP on line 79
这是代码：
public function insert()
{
$MysqL = new DB(debate);
$this->initializeInsert();
$query = "INSERT INTO cards
VALUES('$this->$type','$this->$tag','$this->$author->$last','$this->$author->$first','$this->$author->$qualifications','$this->$date->$year','$this->$date->$month','$this->$date->$day','$this->$title','$this->$source','$this->$text')";
$MysqL->execute($query);
}
(79行是$查询,功能是类卡的一部分)
卡的所有声明：
public $type;
public $tag;
public $title;
public $source;
public $text;
public function __construct() {
$this->date = new Date;
$this->author = new Author;
}
将79行更改为：
$query = "INSERT INTO cards
VALUES('$this->type','$this->tag','$this->author->last','$this->author->first','$this-$author->qualifications','$this->date->year','$this->date->month','$this->date->day','$this->title','$this->source','$this->text')";
我现在得到这个错误：
Catchable Fatal error: Object of class Author Could not be converted
to string in /f5/debate/public/Card.PHP on line 79
阅读约
string parsing,您必须用括号{}括起变量：
$query = "INSERT INTO cards VALUES('$this->type','{$this->author->last}',"
无论何时要访问字符串中属性的多维数组或属性,都必须使用{}包含此访问.否则,PHP将仅解析变量,直到第一个[i]或 – >属性.
所以使用“$this-> author-> last”而不是“{$this-> author-> last}”,PHP只会解析和评估$this->作者,它将错误提供给作者是一个对象.