这是一个jQuery Mobile的问题,但它也涉及纯粹的jQuery.
如何将表单数据发布到没有页面转换的页面设置为表单操作属性.我正在建立phonegap应用程序,我不想直接访问服务器端页面.
我已经尝试了几个例子,但每次形式转发我到目标PHP文件.
介绍
此示例使用jQuery Mobile 1.2创建.如果你想看到最近的例子,那么看看这个article或这个更复杂的one.你会发现2个工作实例解释了很好的细节.如果您有更多的问题请在文章评论部分.
表单提交是一个不断的jQuery Mobile问题.
有几种方法可以实现.我会列出他们中的几个.
示例1：
这是最好的解决方案,以防您使用phonegap应用程序,您不想直接访问服务器端PHP.如果您要创建一个phonegap iOS应用程序,这是一个正确的解决方案.
的index.html
<!DOCTYPE html>
<html>
<head>
<title>jQM Complex Demo</title>
<Meta name="viewport" content="width=device-width,height=device-height,initial-scale=1.0"/>
<link rel="stylesheet" href="http://code.jquery.com/mobile/1.2.0/jquery.mobile-1.2.0.min.css" />
<style>
#login-button {
margin-top: 30px;
}
</style>
<script src="http://www.dragan-gaic.info/js/jquery-1.8.2.min.js"></script>
<script src="http://code.jquery.com/mobile/1.2.0/jquery.mobile-1.2.0.min.js"></script>
<script src="js/index.js"></script>
</head>
<body>
<div data-role="page" id="login" data-theme="b">
<div data-role="header" data-theme="a">
<h3>Login Page</h3>
</div>
<div data-role="content">
<form id="check-user" class="ui-body ui-body-a ui-corner-all" data-ajax="false">
<fieldset>
<div data-role="fieldcontain">
<label for="username">Enter your username:</label>
<input type="text" value="" name="username" id="username"/>
</div>
<div data-role="fieldcontain">
<label for="password">Enter your password:</label>
<input type="password" value="" name="password" id="password"/>
</div>
<input type="button" data-theme="b" name="submit" id="submit" value="Submit">
</fieldset>
</form>
</div>
<div data-theme="a" data-role="footer" data-position="fixed">
</div>
</div>
<div data-role="page" id="second">
<div data-theme="a" data-role="header">
<h3></h3>
</div>
<div data-role="content">
</div>
<div data-theme="a" data-role="footer" data-position="fixed">
<h3>Page footer</h3>
</div>
</div>
</body>
</html>
check.PHP：
<?PHP
//$action = $_REQUEST['action']; // We dont need action for this tutorial,but in a complex code you need a way to determine ajax action nature
//$formData = json_decode($_REQUEST['formData']); // Decode JSON object into readable PHP object
//$username = $formData->{'username'}; // Get username from object
//$password = $formData->{'password'}; // Get password from object
// Lets say everything is in order
echo "Username = ";
?>
index.js：
$(document).on('pagebeforeshow','#login',function(){
$(document).on('click','#submit',function() { // catch the form's submit event
if($('#username').val().length > 0 && $('#password').val().length > 0){
// Send data to server through ajax call
// action is functionality we want to call and outputJSON is our data
$.ajax({url: 'check.PHP',data: {action : 'login',formData : $('#check-user').serialize()},// Convert a form to a JSON string representation
type: 'post',async: true,beforeSend: function() {
// This callback function will trigger before data is sent
$.mobile.showPageLoadingMsg(true); // This will show ajax spinner
},complete: function() {
// This callback function will trigger on data sent/received complete
$.mobile.hidePageLoadingMsg(); // This will hide ajax spinner
},success: function (result) {
resultObject.formSubmitionResult = result;
$.mobile.changePage("#second");
},error: function (request,error) {
// This callback function will trigger on unsuccessful action
alert('Network error has occurred please try again!');
}
});
} else {
alert('Please fill all nececery fields');
}
return false; // cancel original event to prevent form submitting
});
});
$(document).on('pagebeforeshow','#second',function(){
$('#second [data-role="content"]').append('This is a result of form submition: ' + resultObject.formSubmitionResult);
});
var resultObject = {
formSubmitionResult : null
}