我正在使用Symfony和FOSUserBundle,现在我喜欢测试一些东西：
>学说生命周期
>防火墙后的控制器
对于那些测试,我需要是特定用户或至少在用户组中.
如何模拟用户会话以便…
>像“createdAt”这样的生命周期字段将使用登录用户
> Controller就像一些模拟用户登录一样
例：
class FooTest extends ... {
function setUp() {
$user = $this->getMock('User',['getId','getName']);
$someWhereGlobal->user = $user;
// after this you should be logged in as a mocked user
// all operations should run using this user.
}
}
您可以使用
LiipFunctionalTestBundle执行此操作.一旦安装并配置了Bundle,就可以轻松创建和用户并登录测试.
为您的用户创建一个夹具
这将创建一个将在测试期间加载的用户：
<?PHP
// Filename: DataFixtures/ORM/LoadUserData.PHP
namespace Acme\MyBundle\DataFixtures\ORM;
use Doctrine\Common\DataFixtures\AbstractFixture;
use Doctrine\Common\DataFixtures\FixtureInterface;
use Doctrine\Common\Persistence\ObjectManager;
use Acme\MyBundle\Entity\User;
class LoadUserData extends AbstractFixture implements FixtureInterface
{
public function load(ObjectManager $manager)
{
$user = new User();
$user
->setId(1)
->setName('foo bar')
->setEmail('foo@bar.com')
->setPassword('12341234')
->setAlgorithm('plaintext')
->setEnabled(true)
->setConfirmationToken(null)
;
$manager->persist($user);
$manager->flush();
// Create a reference for this user.
$this->addReference('user',$user);
}
}
如果要使用用户组,可以看到official documentation.
在测试中以此用户身份登录
如LiipFunctionalTestBundle’s documentation中所述,以下是如何在数据库中加载用户并以此用户身份登录：
/**
* Log in as the user defined in the Data Fixture.
*/
public function testWithUserLoggedIn()
{
$fixtures = $this->loadFixtures(array(
'Acme\MyBundle\DataFixtures\ORM\LoadUserData',));
$repository = $fixtures->getReferenceRepository();
// Get the user from its reference.
$user = $repository->getReference('user')
// You can perform operations on this user.
// ...
// And perform functional tests:
// Create a new Client which will be logged in.
$this->loginAs($user,'YOUR_FIREWALL_NAME');
$this->client = static::makeClient();
// The user is logged in: do whatever you want.
$path = '/';
$crawler = $this->client->request('GET',$path);
}