我的RESTful文件上传代码：
@Path("/upload")
@POST
@Consumes("multipart/form-data")
public String post(
@FormDataParam("part") String s,@FormDataParam("part") FormDataContentdisposition d) {
return s + ":" + d.getFileName();
}
当我尝试使用curl上传文件时
curl -X POST – 表示part=@file.txt网址
我收到HTTP 415不支持的媒体类型错误.怎么了 ？
解决方法
在尝试了很多例子后,最终在
http://iambigd.blogspot.com/2011/06/java-upload-file-using-jersey.html找到了真正有效的例子
@POST
@Path("/simpleupload")
@Consumes(MediaType.MULTIPART_FORM_DATA)
public void simpleUpload(
//@Context UriInfo ui,@Context HttpServletRequest request
){
String fileRepository = "D:\\";
if (ServletFileUpload.isMultipartContent(request)) {
FileItemFactory factory = new diskFileItemFactory();
ServletFileUpload upload = new ServletFileUpload(factory);
List<FileItem> items = null;
try {
items = upload.parseRequest(request);
} catch (FileUploadException e) {
e.printstacktrace();
}
if (items != null) {
Iterator<FileItem> iter = items.iterator();
while (iter.hasNext()) {
FileItem item = iter.next();
if (!item.isFormField() && item.getSize() > 0) {
System.out.println("File is found.");
String fileName = processFileName(item.getName());
try {
String savePath = fileRepository + fileName;
System.out.println("savePath:" + savePath);
item.write(new File(savePath));
} catch (Exception e) {
e.printstacktrace();
}
}else{
System.out.println("getFieldName:" + item.getFieldName());
System.out.println(item.getString());
}
}
}
}
}
(需要servlet-api.jar,(apache)commons-oi.jar和(apache)commons-fileupload.jar)