<Application x:Class="MusicRepo_Importer.App" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:System="clr-namespace:System;assembly=mscorlib" StartupUri="TestMaster.xaml">
<Application.Resources>
<Style targettype="Window">
<Setter Property="WindowStyle" Value="None"></Setter>
</Style>
</Application.Resources>
</Application>
我基本上希望每个Window都将其WindowStyle的属性值设置为None(删除默认的Windows框架和边框);但它没有用.
我在这里想念的是什么？
在app.xaml / resources ..
<Style x:Key="MyWindowStyle" targettype="Window">
<Setter Property="WindowStyle" Value="None"></Setter>
</Style>
然后在window.xaml ..
<Window x:Class="MusicRepo_Importer.MyWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:sys="clr-namespace:System;assembly=mscorlib"
Title="MyStyledWindow" Style="{StaticResource MyWindowStyle}">
这应该可行,但只是在资源中应用具有targettype for Window的样式将不会强制Window使用该样式,尽管它似乎适用于其他元素.
编辑：
找到一些与将默认样式应用于窗口元素有关的信息.
If you supply a targettype,all
instances of that type will have the
style applied. However derived types
will not… it seems. <Style
targettype=”{x:Type Window}”> will not
work for all your custom
derivations/windows. <Style
targettype=”{x:Type local:MyWindow}”>
will apply to only MyWindow. So the
options areUse a Keyed Style that you specify as
the Style property of every window you
want to apply the style. The designer
will show the styled window.
来自问题：How to set default WPF Window Style in app.xaml?
回答问题的人对从具有应用样式的基本窗口继承有一个有趣的想法.