我想在某些内容开始播放时尝试获取视频链接(例如任何YouTube视频).
首先我抓住视频开始播放
[[NSNotificationCenter defaultCenter] addobserver:self selector:@selector(videoStarted:) name:@"UIWindowDidBecomeVisibleNotification" object:nil];
然后延迟尝试获取链接
-(void)videoStarted:(NSNotification *)notification
{
NSLog(@"notification dic = %@",[notification userInfo]);
[self performSelector:@selector(detectModal) withObject:nil afterDelay:2.5f];
}
-(void)detectModal
{
CUViewController *controller = (CUViewController *)[appDelegate.window rootViewController].presentedViewController;
NSLog(@"Presented modal = %@",[appDelegate.window rootViewController].presentedViewController);
if(controller && [controller respondsToSelector:@selector(item)])
{
id currentItem = [controller item];
if(currentItem && [currentItem respondsToSelector:@selector(asset)])
{
AVURLAsset *asset = (AVURLAsset *)[currentItem asset];
if([asset respondsToSelector:@selector(URL)] && asset.URL)
[self newLinkDetected:[[asset URL] absoluteString]];
NSLog(@"asset find = %@",asset);
}
}
else
{
for (UIWindow *window in [UIApplication sharedApplication].windows) {
if ([window.rootViewController.presentedViewController isKindOfClass:NSClassFromString(@"AVFullScreenViewController")])
{
controller = (CUViewController *)window.rootViewController.presentedViewController;
for(int i = 0; i < [controller.view.subviews count]; i++)
{
UIView *topView = [controller.view.subviews objectAtIndex:i];
NSLog(@"top view = %@",topView);
for(int j = 0; j < [topView.subviews count]; j++)
{
UIView *subView = [topView.subviews objectAtIndex:j];
NSLog(@"sub view = %@",subView);
for (int k = 0; k < [subView.subviews count]; k++)
{
CUPlayerView *subsubView = (CUPlayerView *)[subView.subviews objectAtIndex:k];
NSLog(@"sub sub view = %@ class = %@",subsubView,NsstringFromClass([subsubView class]));
if([NsstringFromClass([subsubView class]) isEqualToString:@"AVVideoLayerView"])
{
NSLog(@"player view controller = %@",subsubView.playerController);
CUPlayerController *pController = subsubView.playerController;
NSLog(@"item = %@",[pController player]);
CUPlayerController *proxyPlayer = pController.playerControllerProxy;
if(proxyPlayer)
{
AVPlayer *player = [proxyPlayer player];
NSLog(@"find player = %@ chapters = %@",player,proxyPlayer.contentChapters);
break;
}
}
}
}
}
}
}
}
}
CUViewController,CUPlayerView,CUPlayerController – 假的类,它看起来像这样
@interface CUPlayerController : UIViewController @property(nonatomic,retain) id playerControllerProxy; @property(nonatomic,retain) id player; @property(nonatomic,retain) id item; - (id)contentChapters; @end
一切都还行,直到这一行
NSLog(@"find player = %@ chapters = %@",proxyPlayer.contentChapters);
球员总是零.也许有更简单的方式来获得媒体链接？
解决方法
首先,我想专注于播放AVPlayerItem的AVPlayer. AVPlayerItem对象携带对该资产的AVAsset对象和表示设置的引用.当您使用AVPlayer的playerWithURL：方法时,它会自动创建由资产支持的AVPlayerItem,该资产是名为AVURLAsset的AVAsset的子类. AVURLAsset具有URL属性.因此,如果您使用它,您可以获得当前播放项目的NSURL.以下是获取URL的示例函数：
-(NSURL *)urlOfCurrentlyPlayingInPlayer:(AVPlayer *)player{
// get current asset
AVAsset *currentPlayerAsset = player.currentItem.asset;
// make sure the current asset is an AVURLAsset
if (![currentPlayerAsset isKindOfClass:AVURLAsset.class]) return nil;
// return the NSURL
return [(AVURLAsset *)currentPlayerAsset URL];
}
我认为这只是你在代码中如何适应这个问题的问题.希望这可以帮助.