在我的’ 
 Swift‘应用程序中,我有一个将照片上传到我的Amazon S3存储桶的功能.当用户连接到WiFi或LTE时,没有问题,但是当连接速度稍慢(例如3G)时,上传需要花费很多时间(最多一分钟),iphone可能会损失15-20%电池!我将照片调整到大约200-300kb,这应该不是问题.我用的代码是: 
  
  
 
func awsS3PhotoUploader(_ ext: String,pathToFile: String,contentType: String,automaticUpload: Bool){
        let credentialsProvider = AWSCognitoCredentialsProvider(regionType:CognitoRegionType,identityPoolId:CognitoIdentityPoolId)
        let configuration = AWSServiceConfiguration(region:CognitoRegionType,credentialsProvider:credentialsProvider)
        AWSServiceManager.default().defaultServiceConfiguration = configuration
        let uploadRequest = awss3transfermanagerUploadRequest()
        uploadRequest?.body = URL(string: "file://"+pathToFile)
        uploadRequest?.key = ProcessInfo.processInfo.globallyUniqueString + "." + ext
        uploadRequest?.bucket = S3BucketName
        uploadRequest?.contentType = contentType + ext
        uploadRequest?.uploadProgress = { (bytesSent,totalBytesSent,totalBytesExpectedToSend) -> Void in
            dispatchQueue.main.async(execute: { () -> Void in
                if totalBytesExpectedToSend > 1 {
                    print(totalBytesSent)
                    print(totalBytesExpectedToSend)
                }
            })
        }
        let transferManager = awss3transfermanager.default()
        transferManager?.upload(uploadRequest).continue({ (task) -> AnyObject! in
            if (task.isCompleted) {
                  print("task completed")
            }
            if let error = task.error {
                 print("Upload Failed ❌ (\(error))")
            }
            if let exception = task.exception {
                 print("Upload Failed ❌ (\(exception))")
            }
            if task.result != nil {
                let s3URL: String = "https://myAlias.cloudfront.net/\((uploadRequest?.key!)!)"
                print("Uploaded to:\n\(s3URL)")
            }
            else {
                print("Unexpected empty result.")
            }
            return nil
        }
        )
} 
 有什么事情让你想到我在这里做错了什么?如何避免这种巨大的电池消耗?
解决方法
 以下答案的灵感来自 
 https://stackoverflow.com/a/20690088/3549695 
  
 
        我相信你需要做的是能够检测无线电网络的类型.无论是WiFi,LTE,3G,2G还是无网络.
然后,应用程序将需要根据结果做出决定.
我创建了一个测试Xcode项目来测试我的iPhone 6上的这个概念.
它似乎工作,但我只能测试’空中飞机模式’,WiFi和LTE.我不能让自己进入2G或3G网络.
如果是WiFi或LTE,我将获得价值:
‘CTradioAccesstechnologyLTE’
在“Air Plane Mode”中,Optional值为零.因此,由我来取代它的文本取决于我.我选择输出’无法检测’
这是我的ViewController.swift的样子:
import UIKit
import CoreTelephony
class ViewController: UIViewController {
    @IBOutlet weak var currentRAN: UILabel!
    override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view,typically from a nib.
    }
    @IBAction func detect(_ sender: UIButton) {
        if case let telephonyInfo = CTTelephonyNetworkInfo(),let currenTradioAccesstech = telephonyInfo.currenTradioAccesstechnology {
            currentRAN.text = currenTradioAccesstech
            print("Current Radio Access Technology: \(currenTradioAccesstech)")
        } else {
            currentRAN.text = "Not able to detect"
            print("Not able to detect")
        }
    }
} 
 .currenTradioAccesstechnology的可能值为:
/* * Radio Access Technology values */ @available(iOS 7.0,*) public let CTradioAccesstechnologyGPRS: String @available(iOS 7.0,*) public let CTradioAccesstechnologyEdge: String @available(iOS 7.0,*) public let CTradioAccesstechnologyWCDMA: String @available(iOS 7.0,*) public let CTradioAccesstechnologyHSDPA: String @available(iOS 7.0,*) public let CTradioAccesstechnologyHSUPA: String @available(iOS 7.0,*) public let CTradioAccesstechnologyCDMA1x: String @available(iOS 7.0,*) public let CTradioAccesstechnologyCDMAEVDORev0: String @available(iOS 7.0,*) public let CTradioAccesstechnologyCDMAEVDORevA: String @available(iOS 7.0,*) public let CTradioAccesstechnologyCDMAEVDORevB: String @available(iOS 7.0,*) public let CTradioAccesstechnologyeHRPD: String @available(iOS 7.0,*) public let CTradioAccesstechnologyLTE: String