我正在尝试使用RawContacts.entityIterator读取所有联系人,但我看到了这个错误：
android.database.Cursorindexoutofboundsexception：索引-1请求
以下是我的代码：
ContentResolver cr = getContentResolver();
Cursor cur = cr.query(Contacts.CONTENT_URI,null,null);
String id = cur.getString(cur.getColumnIndex(Contacts._ID));
if (cur.getCount() > 0) {
while (cur.movetoNext()) {
final Uri uri = RawContactsEntity.CONTENT_URI;
final String selection = Data.CONTACT_ID + "=?";
final String[] selectionArgs = new String[] {id};
final Map<String,List<ContentValues>> contentValuesListMap =
new HashMap<String,List<ContentValues>>();
EntityIterator entityIterator = null;
entityIterator = RawContacts.newEntityIterator(cr.query(
uri,selection,selectionArgs,null));
while (entityIterator.hasNext()) {
Entity entity = entityIterator.next();
for (NamedContentValues namedContentValues : entity.getSubValues()) {
ContentValues contentValues = namedContentValues.values;
String key = contentValues.getAsstring(Data.MIMETYPE);
if (key != null) {
List<ContentValues> contentValuesList =
contentValuesListMap.get(key);
if (contentValuesList == null) {
contentValuesList = new ArrayList<ContentValues>();
contentValuesListMap.put(key,contentValuesList);
}
contentValuesList.add(contentValues);
}
}
}
Log.i(tag,"Contact index=" + id);
}
}
有人可以告诉我我的代码有什么问题.
解决方法
执行查询后,必须调用cur.movetoFirst()…
试试这个
ContentResolver cr = getContentResolver();
Cursor cur = cr.query(Contacts.CONTENT_URI,null);
if(cur != null && cur.movetoFirst())
{
String id = cur.getString(cur.getColumnIndex(Contacts._ID));
if (cur.getCount() > 0) {
...