我可以使用此代码将条目添加到Xmpp帐户.我无法订阅“两者”,而不是我没有得到.
roster.createEntry(“abc@xyz.com”,“abc”,null);
当我订阅此帐户的条目时,如何添加在场类型=两者的条目.我想知道xmpp是否发布 – 订阅功能？
>如何获取入站在线通知？
>如何发送出站在线通知？
编辑：
public void Addcontact() {
Roster.setDefaultSubscriptionMode(Roster.SubscriptionMode.manual);
Roster roster = m_connection.getRoster();
if(!roster.contains("pa@ace.com")) { try {
roster.createEntry("pa@ace.com","pa",null);
} catch (XMPPException e) {
e.printstacktrace();
}
}else {
Log.i("Acc = ","contains");
}
}
我正在添加这样的条目我仍然得到Presence Type = none ..
解决方法
这是我如何在我的应用程序中添加另一个朋友.
protected void doAddContactToListAsync(String address,String name,ContactList list) throws ImException {
debug(TAG,"add contact to " + list.getName());
Presence response = new Presence.Type.subscribed);
response.setTo(address);
sendPacket(response);
Roster roster = mConnection.getRoster();
String[] groups = new String[] { list.getName() };
if (name == null) {
name = parseAddressName(address);
}
try {
// final String name = parseAddressName(address);
// Log.v(tag,msg)
roster.createEntry(address,name,groups);
// If contact exists locally,don't create another copy
Contact contact = makeContact(name,address);
if (!containsContact(contact))
notifyContactListUpdated(list,ContactListListener.LIST_CONTACT_ADDED,contact);
else
debug(TAG,"skip adding existing contact locally " + name);
} catch (XMPPException e) {
throw new RuntimeException(e);
}
}
只需使用必要部分
Presence response = new Presence.Type.subscribed); response.setTo(address); sendPacket(response); Roster roster = mConnection.getRoster(); roster.createEntry(address,groups);
要侦听传入的请求,请将addPacketListener注册到您的连接
mConnection.addPacketListener(new PacketListener() {
@Override
public void processpacket(Packet packet) {
Presence presence = (Presence) packet;
if (presence.getType() == Type.subscribe) {
debug(TAG,"sub request from 1" + address);
//Implement accept or reject depend on user action.
mContactListManager.getSubscriptionRequestListener()
.onSubScriptionRequest(contact);
//or you can test with send back Presence.subscribe first and send Presence.subscribed back to requester.
} else {// Handle other Presence type.
int type = parsePresence(presence);
debug(TAG,"sub request from " + type);
contact.setPresence(new Presence(type,presence.getStatus(),null,Presence.CLIENT_TYPE_DEFAULT));
}
}
},new PacketTypeFilter(Presence.class));
mConnection.connect();
正确的顺序：
> User1发送订阅给user2.
> User2将Subscribe and Subsribed发送回user1.
> User1发送Subribed到user2.
你可以检查另一个SO question