data={
"request": {
"type": "event_and_offer","devicetype": "A"
},"requestinfo": {
"value": "offer"
}
}
如何从volley plz帮助发布此请求
JsonObjectRequest jsonObjReq = new JsonObjectRequest(
Request.Method.POST,url,null,new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response) {
Log.d(TAG,response.toString());
msgResponse.setText(response.toString());
hideProgressDialog();
}
},new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
VolleyLog.d(TAG,"Error: " + error.getMessage());
hideProgressDialog();
}
}) {
/**
* Passing some request headers
* */
@Override
public Map<String,String> getHeaders() throws AuthFailureError {
HashMap<String,String> headers = new HashMap<String,String>();
headers.put("Content-Type","application/x-www-form-urlencoded");
return headers;
}
js是我的jsson对象……我让我的jsson像这样……
JSONObject jsonobject_one = new JSONObject();
try {
jsonobject_one.put("type","event_and_offer");
jsonobject_one.put("devicetype","I");
JSONObject jsonobject_TWO = new JSONObject();
jsonobject_TWO.put("value","event");
jsonobject = new JSONObject();
jsonobject.put("requestinfo",jsonobject_TWO);
jsonobject.put("request",jsonobject_one);
js = new JSONObject();
js.put("data",jsonobject.toString());
Log.e("created jsson","" + js);
但它没有回应plzz帮助的价值
解决方法
首先你的json数据：
JSONObject js = new JSONObject();
try {
JSONObject jsonobject_one = new JSONObject();
jsonobject_one.put("type","event_and_offer");
jsonobject_one.put("devicetype","I");
JSONObject jsonobject_TWO = new JSONObject();
jsonobject_TWO.put("value","event");
JSONObject jsonobject = new JSONObject();
jsonobject.put("requestinfo",jsonobject_TWO);
jsonobject.put("request",jsonobject_one);
js.put("data",jsonobject.toString());
}catch (JSONException e) {
e.printstacktrace();
}
然后你的json请求：
JsonObjectRequest jsonObjReq = new JsonObjectRequest(
Request.Method.POST,js,new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response) {
Log.d(TAG,response.toString());
msgResponse.setText(response.toString());
hideProgressDialog();
}
},new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
VolleyLog.d(TAG,"Error: " + error.getMessage());
hideProgressDialog();
}
}) {
/**
* Passing some request headers
* */
@Override
public Map<String,String> getHeaders() throws AuthFailureError {
HashMap<String,String>();
headers.put("Content-Type","application/json; charset=utf-8");
return headers;
}
注意标题
如果你想在localhost中测试使用下面的代码并设置你的url连接你的localhost服务器和IP地址：
下面的代码将您的所有请求放在一个文本文件中,我尝试了它,它的工作原理
<?PHP
file_put_contents('test.txt',file_get_contents('PHP://input'));
?>