html5 – 从网络摄像头捕获图像

我正在尝试从网络摄像头随机捕获图像,然后将其保存到我的服务器上,现在我正在使用getUserMedia将网络摄像头传输到视频元素,然后我可以使用按钮将图像捕捉到画布,但我不知道如何将该图像从画布保存到我的服务器.

另一个问题是getUserMedia只适用于Chrome,Opera和Firefox,是否有任何替代的IE？

这是我目前正在使用的：

<video id="video" width="640" height="480" autoplay></video>
<button id="snap">Snap Photo</button>
<canvas id="canvas" width="640" height="480"></canvas>
<button id="getBase" onclick="getBase()">Get Base64</button>
<textarea id="textArea"></textarea>

<script>

    // Put event listeners into place
    window.addEventListener("DOMContentLoaded",function() {
        // Grab elements,create settings,etc.
        var canvas = document.getElementById("canvas"),context = canvas.getContext("2d"),video = document.getElementById("video"),videoObj = { "video": true },errBack = function(error) {
        console.log("Video capture error: ",error.code); 
        };

        // Put video listeners into place
        if(navigator.getUserMedia) { // Standard
            navigator.getUserMedia(videoObj,function(stream) {
                video.src = stream;
                video.play();
            },errBack);
        } else if(navigator.webkitGetUserMedia) { // WebKit-prefixed
            navigator.webkitGetUserMedia(videoObj,function(stream){
                video.src = window.webkitURL.createObjectURL(stream);
                video.play();
            },errBack);
        }

        // Trigger photo take
        document.getElementById("snap").addEventListener("click",function() {
            context.drawImage(video,640,480);
        });

        document.getElementByID("getBase").addEventListener("click",getBase());

    },false);                  

    function getBase(){
        var imgBase = canvas.toDataURL("image/png");

        document.getElementByID("textArea").value=imgBase;
    }
</script>`

谢谢堆

<script>
function saveImage(){
    var xmlhttp;
    xmlhttp=((window.XMLHttpRequest)?new XMLHttpRequest():new ActiveXObject("Microsoft.XMLHTTP"));
    xmlhttp.onreadystatechange=function(){
        if (xmlhttp.readyState==4){
            if(xmlhttp.status==200){
                //handle success                
            }
        }
    }
    xmlhttp.open("POST",baseURL,true);
    var oldCanvas = under.toDataURL("image/png");
    var params=oldCanvas;
    xmlhttp.setRequestHeader("Content-type","application/upload");
    xmlhttp.setRequestHeader("Content-length",params.length);
    xmlhttp.setRequestHeader("Connection","close");
    xmlhttp.send(params);
}
</script>

<?PHP
if((isset($GLOBALS["HTTP_RAW_POST_DATA"]))){
    //some validation is necessary,this is just a proof of concept
    if(isset($GLOBALS["HTTP_RAW_POST_DATA"])){
        $params=explode('&',$GLOBALS["HTTP_RAW_POST_DATA"]);
        $imgsrc=str_replace(' ','+',$params[0]);
        $im = imagecreatefrompng($imgsrc);
    }
    if($im){
        $background = imagecolorallocatealpha($im,255,127);
        imagecolortransparent($im,$background);
        //random file name
        $m = rand(10e16,10e24);
        $filename=base_convert($m,10,36);
        //save image
        imagepng($im,'images/'.$filename.'.png');
        imagedestroy($im);
        $size = getimagesize('images/'.$filename.'.png');
        $iH=$size[1];
        $iW=$size[0];
        echo "{\"filename\":\"".$filename."\",\"width\":\"".$iW."\",\"height\":\"".$iH."\"}";
    }
}
?>